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#include<stdio.h> | |
int main(void){ | |
int i, n, k, sum, max, a[100000]; | |
while(scanf("%d %d", &n, &k), n){ | |
sum = max = 0; | |
for(i = 0; i < n; i++){ | |
scanf("%d", &a[i]); | |
if(i < k) | |
sum+=a[i]; | |
} | |
max = sum; | |
for(i = k; i < n; i++){ | |
sum += a[k] - a[k - i]; | |
if(sum > max) | |
max = sum; | |
} | |
printf("%d\n", max); | |
} | |
return 0; | |
} |
DPみたいに解くのかとか考えてたけど、問題見たら"k個の連続する数の和"だったので、単純に入る数と出る数だけ計算すればいいだけだった。
K&R、なかなか進まない……
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